4x-4.9x^2=0.41

Solution for 4x-4.9x^2=0.41 equation:

4x-4.9x^2=0.41

We move all terms to the left:

4x-4.9x^2-(0.41)=0

We add all the numbers together, and all the variables

-4.9x^2+4x-0.41=0

a = -4.9; b = 4; c = -0.41;
Δ = b2-4ac
Δ = 42-4·(-4.9)·(-0.41)
Δ = 7.964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{7.964}}{2*-4.9}=\frac{-4-\sqrt{7.964}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{7.964}}{2*-4.9}=\frac{-4+\sqrt{7.964}}{-9.8}
$